BÀI 1 :
Sắp xếp các số sau theo thứ tự từ nhỏ đến lớn :
A = ( 649+ 13 . 180) - 13 . ( 2 . 649 . 180)
B =
C =
Bài làm :
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Không viết vào phần
gạch chéo này
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BÀI 2 :
a) Cho biết tỷ số của y - 13 và 7x + 5 là hằng số và y = 20 khi x = 2 .
Hỏi khi y = 2004 thì x bằng bao nhiêu ?
b) Bốn người góp vốn để thành lập công ty TNHH . Sau 5 năm, tổng số tiền lãi nhận được là 9 902 490 255 đồng và được chia theo tỷ lệ giữa người thứ hai và người thứ nhất là 3 : 2 ; tỷ lệ giữa người thứ ba và người thứ hai là 5 : 4 ; tỷ lệ giữa người thứ ba và người thứ tư là 6 : 7 . Hỏi số tiền lãi mỗi người nhận được là bao nhiêu ?
Bài làm :
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BÀI 3 :
Cho dãy số : U = với
1) Tính 8 số hạng đầu tiên của dãy này .
2) Lập một công thức truy hồi để tính U theo U và U .
3) Viết qui trình bấm phím liên tục để tính Utrên máy .
4) Tìm tất cả các số tự nhiên n để U 3 .
Phßng Gi¸o dôc H¹ Long Thi chän häc sinh giái cÊp thµnh phè ----------------------------- N¨m häc 2004-2005 ------------------------ Ch÷ ký gi¸m thÞ 1: ................... 2: ................... M«n thi : Gi¶i To¸n trªn m¸y tÝnh CASIO Ngµy thi : 05/12/2004 Thêi gian lµm bµi : 150 phót ( kh«ng kÓ thêi gian giao ®Ò ) Sè ph¸ch Hä vµ tªn thÝ sinh : ................................................................ Ngµy sinh : ................................. Sè b¸o danh : ................... N¬i sinh : .............................................................................. Häc sinh trêng : .................................................................. $.................................................................................................................................................................. Sè ph¸ch §iÓm bµi thi : B»ng sè :................. ( B»ng ch÷ : ....................................................) Ch÷ ký cña hai ngêi chÊm thi : : 1: .................................... 2 : ............................... * Ghi chó : - ThÝ sinh lµm bµi ngay vµo ®Ò thi nµy . §Ò thi gåm 02 tê . ( Tê sè 1 ) - C¸c bµi ë nh÷ng bíc dïng m¸y tÝnh ®Ó t×m kÕt qu¶ ph¶i viÕt qui tr×nh bÊm phÝm . - NÕu kh«ng nãi g× thªm, h·y tÝnh chÝnh x¸c ®Õn 6 ch÷ sè . ___________________________________________ Bµi 1 : S¾p xÕp c¸c sè sau theo thø tù tõ nhá ®Õn lín : A = ( 649+ 13 . 180) - 13 . ( 2 . 649 . 180) B = C = Bµi lµm : .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. Kh«ng viÕt vµo phÇn g¹ch chÐo nµy $.................................................................................................................................................................... Bµi 2 : a) Cho biÕt tû sè cña y - 13 vµ 7x + 5 lµ h»ng sè vµ y = 20 khi x = 2 . Hái khi y = 2004 th× x b»ng bao nhiªu ? b) Bèn ngêi gãp vèn ®Ó thµnh lËp c«ng ty TNHH . Sau 5 n¨m, tæng sè tiÒn l·i nhËn ®îc lµ 9 902 490 255 ®ång vµ ®îc chia theo tû lÖ gi÷a ngêi thø hai vµ ngêi thø nhÊt lµ 3 : 2 ; tû lÖ gi÷a ngêi thø ba vµ ngêi thø hai lµ 5 : 4 ; tû lÖ gi÷a ngêi thø ba vµ ngêi thø t lµ 6 : 7 . Hái sè tiÒn l·i mçi ngêi nhËn ®îc lµ bao nhiªu ? Bµi lµm : .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. 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Bµi 3 : Cho d·y sè : U = víi 1) TÝnh 8 sè h¹ng ®Çu tiªn cña d·y nµy . 2) LËp mét c«ng thøc truy håi ®Ó tÝnh U theo U vµ U . 3) ViÕt qui tr×nh bÊm phÝm liªn tôc ®Ó tÝnh Utrªn m¸y . 4) T×m tÊt c¶ c¸c sè tù nhiªn n ®Ó U 3 . Bµi lµm : .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. .................................................................................................................................................................................................................................................................................................................................................................................................................................... ... 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Bµi 7 : Cho ®êng trßn t©m O b¸n kÝnh R = 3,15 (cm) . Tõ mét ®iÓm A ë ngoµi ®êng trßn kÎ 2 tiÕp tuyÕn AB vµ AC ( B vµ C thuéc ®êng trßn t©m O ) . BiÕt AO = a = 7,85 (cm) . a) TÝnh gãc BOC vµ diÖn tÝch cña phÇn mÆt ph¼ng giíi h¹n bëi hai tiÕp tuyÕn AB ; AC vµ cung nhá BC . b) ViÕt qui tr×nh bÊm phÝm liªn tôc trªn m¸y ®Ó tÝnh ®îc gãc b»ng gãc BOC vµ diÖn tÝch ®· nãi ë trªn . Bµi lµm : .................................................................................................................................................................................................................................................................................................................................................... .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. .................................................................................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................................................................................... .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. .................................................................................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................................................................................... .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. .................................................................................................................................................................................................................................................................................................................................................... .................................................................................................................................................................................................................................................................................................................................................... .............................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................. ....................................................................................................................................................................................................................................................................................................................................................
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